$\frac{81}{121}m^4-\frac{64}{256}n^{12}$
$-26-\left(-14\right)-20+\left(-2\right)$
$-3x^2\left(x^2-2x+3\right)$
$x^2+y^2+z^2=z$
$\sqrt[3]{64}\cdot\sqrt[3]{27}$
$\left(-4\right).\left(-1\right)$
$\infty+\infty-1$
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