$2xb+3xb$
$7y^2-7y$
$\frac{dy}{dx}=\frac{x}{7\cos\left(y\right)}\:$
$2\sin\left(x\right)\cos\left(x\right)+2\sin\left(x\right)\cos\left(x\right)$
$\frac{5a\sqrt[3]{x^2}}{3x}$
$-3x^2+12=-5x^2+20$
$1+sin^2x=cos^2x$
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