$\left(\frac{2}{5}x+4\right)^2$
$\left(3m+10n\right)\left(3m-10\right)$
$\int\frac{x^2+20x-7}{\left(x^2+1\right)\left(4x^2+9\right)}dx$
$35+21-6+27+4$
$1x^3+8x^2+x+8$
$4^2.4^3$
$\int\frac{x^{3}}{\left(x^{2}+2\right)^{2}}dx$
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