$\int\:\frac{3x^3+4x^2+3x}{x^2+1}dx$
$( 6 x ^ { 2 } y ^ { 4 } ) ( - 3 x ^ { 4 } y ^ { 4 } )$
$1-\left(x-1\right)^2$
$\frac{5x^2}{2}-3+1$
$\int\:2\:tdt$
$\int_0^{\frac{\pi}{3}}\left(\frac{1}{1-\sin\left(x\right)}\right)dx$
$\frac{0.48}{0.06}\:=\:\frac{2.4}{3}$
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