$( 4 + x ) y ^ { 2 } = y ^ { 3 }$
$\frac{dy}{dx}\left(x^3\tan\left(x\right)-\sqrt{x}\right)$
$27x^2+16x-81$
$\left(1+x^2\right)y'\:=\:1+y^2$
$\left|4\right|+9$
$7x^2y-7x^2y$
$-\left(-\frac{1}{3}\left(-1\right)^3-4e\left(-1\right)\right)$
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