$\arccos x=2\:arccos\left(\frac{3}{4}\right)$
$\left(3y-4x\right)^2$
$\int\left(\frac{1}{4\sqrt[8]{x^7}}\right)dx$
$\left(3x^3+6x\right)\left(3x^3-6x\right)$
$bx-4x-3b+12$
$a+b=-5$
$-3a^2+3a$
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