$4x+8y-4z=4$
$\left(z+8\right)^3$
$\left(2-\frac{1}{2w}\right)^2$
$x\cdot\frac{dy}{dx}=\frac{1}{4ye^{2y}}$
$\int\frac{6}{x^2-x-2}dx$
$\left(2.30\right)\cdot\left(-30.6\right)$
$27\:+\:y\:=\:\:-\:13$
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