$y'=y^2\:\sec x$
$\frac{dy}{dx}=\frac{\cos^2\left(y\right)}{\sin^2\left(x\right)}$
$3x^2+4xy-2y^3;\:x=-3;\:y=2$
$\int\left(\frac{e^{2x}}{2e^{2x}+5}\right)dx$
$\left(3x\:+\:3y\right)^5$
$\frac{15a}{\left(-5\right)}$
$\frac{w}{7}+6w+63$
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