$4^{x+3}=\left(\frac{1}{2}\right)^x$
$\left(3w^2\right)^3$
$3x+4<13x+12$
$\sqrt[3]{216\cdot64}$
$y^2+2y$
$\left(\sqrt{x+by}\left(\sqrt{x}\right)\right)$
$\left(a-3b\right)\left(a^2+3ab+9b^2\right)$
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