$\frac{\cos^2\left(x\right)\sin\left(x\right)}{\sin^2\left(x\right)\cos\left(x\right)}$
$\frac{\infty}{-\infty-\infty-6}$
$\frac{1}{3x}-\frac{1}{x\left(x+3\right)}$
$\frac{3x^4-8x^3+9x+5}{x-2}$
$t^2+18t+81$
$-9\cdot14$
$6xz-16y-24+4xy$
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