$\lim_{x\to\infty}\left(\frac{9x}{ln6x}\right)$
$\frac{9\left(\frac{1}{3}\right)^2}{3}^-\frac{8\left(\frac{1}{2}\right)^2}{2}+3$
$\left(2a^2-15a\right)\cdot\left(-17a-a^2\right)$
$\frac{dy}{dt}=-\frac{4y}{t}$
$2\cdot3^2+2\cdot5-12$
$34,02+129,983$
$9x^2-12x-5$
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