$\frac{1}{\infty^2}$
$\frac{6x-18}{x^2-3x}$
$\int_{-3}^{-1}\left(-4x\right)dx$
$25x+9x^2+16$
$\int\frac{288}{x^3-36x}dx$
$\int12x^2\left(x^3-7\right)^5dx$
$g-8=\:-4$
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