$\left(x+3\right)+\left(x+5\right)$
$3y-2x-3-5$
$5x=-35$
$x'=\frac{1}{x^3}$
$\left(2x^3-3x^2+10x-6\right)\left(x^2-2x\right)$
$\lim_{x\to3}\left(\frac{x^{3}-27}{x-3}\right)$
$\lim_{x\to1}\left(\frac{8x^2+4x-6}{4x-3}\right)$
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