$\lim_{x\to\infty}\left(4x\left(tan\left(\frac{7}{x}\right)\right)\right)$
$\left(-3\right)^{2^{2^1}}$
$-\infty2$
$\frac{d}{dx}\frac{3x^2-1}{2y}$
$\left(x+a\right)\left(x+a\right)\left(x+a\right)\left(x+a\right)\left(x+a\right)$
$3x^2-6x-5=0$
$2\cdot9-7$
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