$4^3-2\cdot5^2+9$
$\frac{9b^2y}{27by}$
$a^3+b^3=14$
$\:\frac{3}{7}x=0$
$5x+6>8\left(x-6\right)$
$345+214$
$\frac{x^3-6x^2+15}{x-2}$
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