$\int\frac{8x+8}{x\left(x+2\right)^2}dx$
$3z^2-10;\:z=2$
$-x^3-x-5$
$45\cdot9$
$-3\cos\:2\theta-18\sin\theta\:-8=-5\sin\theta\:-6$
$\frac{dy}{dx}=\frac{y}{\left(e^{\left(2x\right)}+4\right)}$
$s^2+s-1$
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