$\frac{5x^3}{5x+10}\cdot\frac{x^2-4}{x^2}$
$x^2\:-\:2x\:-\:4$
$\frac{2a\cdot\left(4b+6c\right)}{\left(6c-2a\right)\cdot2a}$
$5x^2+20x=0$
$\frac{1}{3x\left(3x\right)}$
$-17-1+18+6+4+4$
$7a^2-35=44a$
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