$\lim_{x\to0}\left(\frac{\left(ln\left(x\right)\right)^3}{ln\left(4x\right)}\right)$
$2<-8-u$
$x^2-4x-32$
$\frac{3\sqrt{32}-2\sqrt{8}}{\sqrt{8}}$
$\left(5^{-1}\right)\:-\:\left(5^0\right)$
$cot\theta\:=\frac{\sqrt{3}}{3}$
$\left(3a^2\right)\left(4a^6\right)$
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