$x^2-3x\le0$
$\int\frac{\left(5x^2-36x+48\right)}{x\left(x-4\right)^2}dx$
$\lim_{x\to0}\left(\frac{tan\left(5x\right)-5x}{x^3}\right)$
$39^2-36^2$
$x^2y-3xy'+4y=0$
$9r^2+42rz+49z^2$
$\left(-5\right).14+\left(-5\right).6$
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