$\frac{1}{cos-jsin}$
$\frac{5x^3+3x^2+5x-7}{x^2+5}$
$2x^2\:-\:5x\:+\:1\:+\:3x^2\:-\:3x\:-\:4$
$2x^5+3x^4+2x^3+x$
$\frac{\tan\left(a\right)}{\cos^2\left(a\right)}=\frac{1+\tan^2\left(a\right)}{\cot\left(a\right)}$
$5+3\cdot\left(-2\right)-\left(-7+3\right)$
$\lim_{x\to0}\left(\frac{2x-\pi}{\cos x}\right)$
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