$\int\:te^{6t}dt$
$\sqrt{2y^2u^5}\cdot\sqrt{10yu^4}$
$\frac{x^3+3}{x^2-1}$
$\frac{dy}{dx}+0.196y=9.8$
$4x-2y-11y-7x-3$
$y^2-x^2=cx$
$0.06\cdot10^5\cdot23.2\cdot10^{-7}$
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