$\frac{4}{x}=\frac{-1x}{5}$
$-3x+8<-15$
$\left(\sqrt{3}\right)\left(\sqrt{2}\right)^2$
$x\left(2+11x\right)$
$\frac{7}{6}-\frac{1}{6}$
$4ab-2ac+12ad$
$\left(2x-1+3x\right)-\left(-6-5-4-3x+2+5x^2\right)$
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