$2sin^2x=1-sinx$
$5-5e^{0.12x}$
$16x^2-4x+16$
$2a^2-3b+4a^2+3b+2a$
$\lim_{x\to0}\left(\frac{3e^x-4x+e^{-3x}}{2x^2}\right)$
$-2+3-\left(-4\right)\left(-4\right)$
$\left(1+x\right)\left(x-1\right)^4$
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