$\left(10x^2+19x+6\right)\left(10x^2+19x+6\right)$
$x^2-3x+8$
$3x-12=-18$
$2x-5<x-6$
$2^{2}+2+1\sqrt{a^{3}-a^{2}-1a-1}$
$100r^2-160r+64$
$x+5=14-\frac{1}{2}x$
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