$1-\frac{sin^2\left(x\right)}{1+cos\left(x\right)}=-cos\left(x\right)$
$\int_1^{\infty}\left(\frac{1}{x^{.8}}\right)dx$
$x+5=-2$
$\left(x^4-3x^3+4x^2+3x-5\right):\left(x-5\right)$
$x+1=2x+8$
$4^2+3x+-11$
$\lim_{x\to0}\left(e\right)^x+1$
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