$\frac{4x-8}{3}<x+5$
$\frac{1000^3-8^3}{6x-8y}$
$y'=\frac{3x^2+4x-4}{2y-4},\:y\left(1\right)=3$
$\lim_{x\to0}\left(\left(1-6x\right)^{\frac{1}{x}}\right)$
$\frac{x}{-2}-5\le\:-10$
$\frac{2}{5}=\frac{x}{10}$
$\sqrt{18m^2n^3}+m\sqrt{32n^3}-5\sqrt{2m^2n^3}$
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