$\frac{y^9}{y^5}$
$3x^2+25x+63$
$\left(x^3+8\right):\left(x+2\right)+\left(x-4\right)^2$
$6tan^2x=2$
$3b^210b-8$
$\int\left(8x\sqrt{9-8x^2}\right)dx$
$e^{-y}=1+cx$
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