$3y^4-2x^3y+4x^3-5y^4x+3;\:x=-2;y=3$
$\lim_{x\to9}\left(\frac{\frac{1}{x+5}-\frac{1}{14}}{x-9}\right)$
$3\:3x^2+4x$
$x+3+2x-9$
$3x^2-5x=8$
$\frac{52.5}{2}$
$4^2+6$
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