$\frac{1}{cos\left(x^3\right)}\frac{dy}{dx}=\frac{3x^2}{2y}$

$y=\sqrt[3]{x^2+x+1}$

$y^2-9y+8$

$a^4+a^2b^2+\frac{b^4}{4}$

$\left(t^2+11\right)\left(t^2-11\right)$

$\cos255^{\prime}=\frac{\sqrt{2}-\sqrt{6}}{4}$

$\left(4+\left(8-\left(5-2\right)+\left(7-3\right)\right)+\left(\left(-3\right)-\left(-8\right)+13\right)\right)$