$-9+\left(-7+6-1\right)-\left(-2+4-1\right)$
$5.\:-6\:-\:25$
$f\left(x\right)=5\left(2x^2-7x+3\right)^{-3}$
$-2\cdot3\cdot5$
$\lim_{x\to0}\left(\frac{x^2}{x-sinx}\right)$
$\frac{5x^2-36+48}{x\left(x-4\right)^2}$
$\frac{5x-6}{2}>x+2$
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