$5a-17^2+2a+4^2$
$y'\:-y=16$
$1x^2+2x+\left(\frac{2}{2}\right)^2$
$7\left(-3\right)\left(-2\right)\left(-4\right)$
$x^2-7^3-1$
$\lim_{x\to\infty}\left(\frac{x-2}{x}\right)^2$
$\int\frac{x^2+x}{\left(x^2+4\right)\left(x+2\right)}dx$
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