$12+36+15-3-6.\left(-9\right)$
$\lim_{x\to\infty}\left(\frac{lnx^4}{ln\left(x+1\right)^4}\right)$
$\int\frac{x^2+19x+36}{x\left(x^2+7x+12\right)}dx$
$\int\left(49+x^2\right)^{-6}dx$
$5\left(6-5-2-12\right)$
$3,54-8,53$
$\frac{1}{1-8x^3}$
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