$\sqrt[15]{5.5^6}$
$\left(9x+4y\right)^3$
$\sqrt{x},\:en\:x=4$
$3x^2y-6xy^2+12x\left(-6x^2+3x+1\right)$
$\frac{\left(1+cot^2\left(x\right)\right)\left(cos^2\left(x\right)\right)}{cot^2\left(x\right)}=1$
$5x-6>11$
$\left(\frac{1}{3}x^3+4y^2\right)^2$
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