$48-24x+3x^2\:$
$\left(5xy^2+4x^2y\right)^2$
$3lnx+5$
$f\left(x\right)=\frac{3x^2-5}{\left(3x^2-5\right)^{15}}$
$3a^2\:b+3ab^4-3abc$
$-4a\:-\:2b\:+\:3b$
$\tan\left(-\frac{5\pi}{4}\right)-\cot\left(\frac{7\pi}{2}\right)$
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