$\int\sqrt{1+\left(tan\left(8x\right)\right)^2}dx$
$\frac{dy}{dx}=\frac{1}{\sqrt[3]{x+2}}$
$\frac{-5^1}{-5^0}$
$\frac{dy}{dx}=\frac{\left(2y^2+4x^2\right)}{xy}$
$4-2^2$
$\lim_{x\to4}\left(\frac{x^2+3x}{x^2-x-12}\right)$
$4a^4+8a^2a^2+9b^4$
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