$\frac{1}{1+tan^2}\:=\:cos^2$
$x2\:+6x\:-12\:=\:0$
$16^{12}$
$\frac{dy}{dx}=\frac{-0.01\cdot x}{y}$
$\sin\left(x\right)^2\cos\left(x\right)^2=\frac{1-cos\left(4x\right)}{8}$
$2x-1>7$
$\frac{x-2}{2x}+\frac{x-1}{x}+\frac{x+1}{x}$
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