$\lim_{x\to\infty}\left(8-\frac{4\left(x+1\right)\left(2x+1\right)}{3x^2}\right)$
$\frac{4y^2}{25}-100$
$simplfy\:2cos\left(x+y\right)cos\left(x-y\right)\:-cos\left(2x\right)$
$\left(3x^2-2x-8\right)-\left(6x^2-5x\right)$
$\left(6^{-1}\right)^{16}$
$-2xy\left(4x^2y^3-3x^5y^2\right)$
$\left(5+y^2\right)^3$
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