$\lim_{x\to0}\left(\frac{\frac{\sin}{\cos}.\frac{\sin}{\cos}}{x}\right)$
$1+-3+-5+7$
$c^3+4c-4c^3$
$\frac{2x^2-7x+9}{2x-5}$
$\left(\frac{1-x}{y}\right)dx=-x^2\cos\left(y\right)dy$
$\frac{x^2-4}{x^3-10}$
$\frac{x+6}{x-4}=\frac{1}{x+1}$
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