$-x^2-4x+5$
$\frac{tan\left(2x\right)}{tan\left(5x\right)}$
$\frac{sec\left(-t\right)}{cot\left(t\right)+tan\left(t\right)}$
$6d^4+9d^3$
$\frac{d^2}{dx^2}\left(x^3+y^3=8\right)$
$4<x^2$
$3b+2c=-4$
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