$\frac{12x^3+10x^2+11x+12}{3x+1}$
$\lim_{x\to-2}\left(\frac{\:\left(x^3+8\right)}{\left(x+2\right)}\right)$
$2x-8>x+1$
$x^{4}-2x^{3}-8x+16$
$1.0125^{20}$
$\frac{x+3}{4}>-2x-6$
$\cos\left(x-\frac{\pi}{2}\right)=\cos\left(x\right)\tan\left(x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!