$\frac{x+1}{x}=\frac{1}{x}$
$\lim_{x\to-\infty}\left(\frac{\sqrt{4x^4-x}}{2x^2+3}\right)$
$\frac{c^9\:d^{-7}}{c^{14}\:d^{-10}}\:$
$\sqrt{\frac{2x}{9}}$
$\frac{dy}{dx}=\frac{xe^{x^2}+2x}{6y^2}$
$55\left(-34\right)-12$
$4a\left(-6b+8z\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!