$\frac{d^{-19}}{6}$
$r^{2}-9r$
$\frac{1}{x+3}\le2$
$\left(x-40\right)\left(x+7\right)$
$\left(6c+5n\right)^2\left(w-9\right)$
$4a^2-6a^2+8a+19a^4$
$\frac{6^4.6^3}{6^2.6^5}$
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