$\frac{v}{-3v^2}$
$\left(-3+\frac{6b}{n}\right)^2$
$\frac{\left(3a^3+2\right)^2-\left(3a^3-2\right)^2}{12a^2}$
$-30+18-\left(-7\right)+1-5-\left(6\right)+\left(-7\right)$
$\sqrt{8}0\:x^2y^8\:\:$
$\left(3a^3-2b^4\right)^2$
$\frac{y^2+3y-11}{y+5}$
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