$\int_{6x}^4t\cdot sin\left(2t\right)dt$
$5^5\cdot2^4\cdot2^2$
$\left(secx+tanx\right)\frac{1+sinx}{cosx}=1$
$\frac{m^{-3}n^2}{mn^3}$
$\left(3x+4\right)\left(2x^2-x+4\right)$
$\frac{2}{3x+1}=\frac{5}{6x+2}$
$400x^{10}+40x^5+2$
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