$4x^3+10x^3$
$4x^6-12\cdot3+9$
$\left(-6\right)\left(-4\right)\left(-2\right)\left(-1\right)$
$\frac{y}{3}-2=1$
$+4x-x^2+7x-\frac{1}{2}+x+x^2+1$
$\frac{5}{6}-a^3b^4\frac{-3}{10}a^4b^2c$
$\left(5x-3y-8z\right)^2$
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