$\frac{\left(1-x\right)^3+\left(y+1\right)^3}{\left(1-x\right)+\left(y+1\right)}$

$\left(0.08\cdot57\right)+18$

$\int_0^2\left(x^3-3x^2+3x-\left(x\right)\right)dx$

$\left(6-10\right).\left(11-13+7\right)-\left(4-6+5\right).\left(1-7-4\right)$

$\frac{3y^{-1}}{4yx^3}$

$\frac{dy}{dx}=6+e^{-7x}$

$\frac{dy}{dx}y^2=x+1$