$\left(1+tan\theta\:\right)^2$
$\sqrt{16a^{16}}$
$\left(-20\right)\cdot7$
$2x^2-6x+9$
$\sec\left(-u\right)$
$\left(-5\right)\left(-12\right)\left(-18\right)$
$\frac{\left(\sqrt[7]{x}-9\right)}{\sqrt[7]{x^6}}$
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