$\frac{3}{2}+3x<0$
$6.25\cdot10^6$
$\frac{\sec^6x-\tan^6x}{\cos^2\left(x\right)}$
$\frac{1+\cos^2\left(45^{\circ}\right)}{\sec^2\left(45^{\circ}\right)}+\left(\text{sen}\left(45^{\circ}\right)-\cos\left(45^{\circ}\right)\right)^2=1$
$x+5>1-3x$
$\left(-9\right)-7\left(-2\right)-\left[1-\left(-3\right)\right]$
$f\left(x\right)=\frac{x\left(x^2-5\right)^2}{x-8}$
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