$\tan^2x-\tan\left(x\right)=0$
$\int\left(12x^2-10x\right)\left(4x^3-5x^2\right)\:dx$
$0=\frac{\tan a}{\sin a}-\sec a$
$\int9sin\left(5x+8\right)dx$
$3 y = 0$
$\lim_{x\to\infty}\:\frac{\sqrt[n]{x}}{lnx}$
$\frac{4.1\:\:-4}{\left(4.1\right)^2-3\left(4.1\right)-4}$
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