$\lim_{x\to-1}\left(\frac{7x^4+4x^3+5x+2}{x+1}\right)$
$17-\left(-10\right)$
$8y+32$
$5+x=17-2x$
$x^2\sin\left(x\right)dx+xydy=0$
$\frac{4x^5}{x^3}+\left(-3x^2\right)$
$\frac{\cos\:\left(x\right)-1}{sin\left(x\right)}=\frac{sin\left(x\right)}{cos\left(x\right)+1}$
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